2x+8=3kx (3k-2)x+8=0
3x-kx=2. (3-k)x-2=0
3k-2)x+10=3-k)x
4k-5=10/x
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3x-y-2=2x+8-3y
X+2y-10=0
X+2kx-10=0
K=(10-x)/2x
Selecting this function: F(x)= x^4-x^2+3
Graph using these selected points:
Rises to the left and rises to the right
x y
-1 3
0 3
1 3
2 15
3 75
After assigning values for x and y, plot the graph:
See attached picture for the graph.
We can now conclude that for the given graph, the equation of F(x) is equal to x^4-x^2+3 which is letter
D. F(x)= x^4-x^2+3
Answer:
x^2+(y-1)^2=25
Step-by-step explanation:
eqn of circle : (x-h)^2+(y-k)^2=r^2
center of circle = (h,k)
hence, the center of the current circle is (2,3)
moving 2 units to the left would make the center (0,1)
the radius would remain the same (5) , hence the new eqn would be
(x-0)^2+(y-1)^2=25
x^2+(y-1)^2=25