Which could be the length of the third side of a triangle with side lengths 3ft and 9ft? explain

Please help me with this pleaseee

torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = $\frac{opposite}{adjacent}$ = $\frac{500}{x}$

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = $\frac{500}{tan80}$ ≈ 88.2

5 0

3 years ago

A basketball player has made 70% of his foul shots during the season. If he shoots 3 foul shots in tonight's game, what is the

yulyashka [42]

Answer:

There is a 34.3% probability that he makes all of the shots.

Step-by-step explanation:

For each foul shot that he takes during the game, there are only two possible outcomes. Either he makes it, or he misses. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 3, p = 0.7$

What is the probability that he makes all of the shots?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.7)^{3}.(0.3)^{0} = 0.343$

There is a 34.3% probability that he makes all of the shots.

7 0

3 years ago

There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

guajiro [1.7K]

Answer:

Sixth graders: 14

Seventh graders: 28

Eighth graders: 28

Step-by-step explanation:

To solve this you just have to use a rule of three to solve the percentages, remember that the 100% will be the 70 students, and we solve each case separetly:

70 students= 100%

sixth grades= 40%

Sixth grades= (40*70)/100

Sixth graders= 28

70 students= 100%

seventh grades= 20%

seventh graders= (20*70)/100

Seventh graders=14

So if we have that the rest of the students are eighth graders, we just add up the sixth and seventh graders and withdraw them from the total:

28+14=42

70-42=28

SOwe have that the eighth graders are 28