Answer:
From this term
, we cannot remove variable as they are not in square form .
Thus we look at number 75
75 = 25 × 3
25 is a perfect square , so it can come out and this we get 5 when its removed
Thus the answer is ![5\sqrt{3yz}](https://tex.z-dn.net/?f=5%5Csqrt%7B3yz%7D)
I hope it helps you
#Indian : )
Answer:
the answersiub be b37647bbuebvevwvuwfvhwebfvbwecwjhvwvevfedv
Step-by-step explanation:
guikbddghvdegvedvc sdvvdxvsgv xsv xdvgedve ccedvvdwv
Answer:
![w \in (0,41)](https://tex.z-dn.net/?f=w%20%5Cin%20%280%2C41%29)
where w is width of rectangle.
Step-by-step explanation:
We are given the following in the question:
The perimeter of a rectangle must be less than 170 feet.
Length of rectangle = 44 feet
Perimeter of rectangle =
![2\times (\text{Length + Width})](https://tex.z-dn.net/?f=2%5Ctimes%20%28%5Ctext%7BLength%20%2B%20Width%7D%29)
Let w be the width of rectangle.
According to the question,
![P < 170\\2(44 + w)](https://tex.z-dn.net/?f=P%20%3C%20170%5C%5C2%2844%20%2B%20w%29%3C170%5C%5C44%20%2B%20w%20%3C%2085%5C%5Cw%20%3C%2041)
Thus, the width of triangle should be less than 41. Since w cannot take negative values, we can express value of w in interval notation as,
![w \in (0,41)](https://tex.z-dn.net/?f=w%20%5Cin%20%280%2C41%29)
Add the 2 and 9 together:
2q+11