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3 years ago

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What is the difference between the greatest amount and least amount of gasoline used to mow lawns?

1 answer:

weqwewe [10]3 years ago

4 0

Answer:
The difference is 4/8 which is equivalent to 1/2

Explanation:
The given values of gasoline amounts are as follows:
1/8 , 2/8 , 3/8 , 4/8 , 5/8

Since all the values have the same denominator, therefore, we can base our comparison on the numerator. The larger the numerator, the larger the value of the fraction.

Based on this, we can note that:
the least amount of gasoline is 1/8
the greatest amount of gasoline is 5/8

The difference between the two can be computed as follows:
difference = greatest amount - least amount
difference = 5/8 - 1/8
difference = 4/8 which can be simplified to give 1/2

Hope this helps :)

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Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

Or

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

This is a parabola (0,2.5) and turns upside down.

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What is the simplified expression for:

kari74 [83]

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I hope this helps! Good luck!

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Xelga [282]

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-4/9 repeating decimal

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