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3 years ago

What is the difference between the greatest amount and least amount of gasoline used to mow lawns?

1 answer:

4 0

Answer:
The difference is 4/8 which is equivalent to 1/2

Explanation:
The given values of gasoline amounts are as follows:
1/8 , 2/8 , 3/8 , 4/8 , 5/8

Since all the values have the same denominator, therefore, we can base our comparison on the numerator. The larger the numerator, the larger the value of the fraction.

Based on this, we can note that:
the least amount of gasoline is 1/8
the greatest amount of gasoline is 5/8

The difference between the two can be computed as follows:
difference = greatest amount - least amount
difference = 5/8 - 1/8
difference = 4/8 which can be simplified to give 1/2

Hope this helps :)

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6d+23=14(d−2) what is the answer

Amanda [17]

6d+23=14(d-2)
6d+23=14d-28
6d+51=14d
51=8d
51/8= 6.375 or 6 3/8

Hope this helps :)

4 0

3 years ago

Read 2 more answers

Vectors; please help: 2y+w-u=?

andreyandreev [35.5K]

Answer:

idkdikdidkidkidk

Step-by-step explanation:

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3 years ago

What is the slope of a line that passes through (–4,–13) and (19,11)?

Anna11 [10]

For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)

(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11

slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer

5 0

3 years ago

Read 2 more answers

What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b square

geniusboy [140]

Answer:

$x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}$

Step-by-step explanation:

So the question here is asking you to use the quadratic formula which is expressed as: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

A quadratic can generally be expressed as: $y=ax^2+bx+c$

So using the equation you gave: $0=x^2-5x-1$

We can identify the following values: a=1, b=-5, c=-1

Btw the equation explicitly write "1" as the coefficient of x, but since it's not provided it's implied that it's 1.

So plugging in the known values, we get the following equation:

$x=\frac{5\pm\sqrt{(-5)^2-4(1)(-1)}}{2(1)}\\\\x=\frac{5\pm\sqrt{25+4}}{2}\\\\x=\frac{5\pm\sqrt{29}}{2}\\\\x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}$

The last step just consists of taking the + and - solution, and since it asks for exact solutions you leave the 29 under the radical, and you don't approximate. There is no further simplification that can be done here.

5 0

2 years ago

Simplify this problem::<br> -6x + 3 3/4 + 14x - 3.25

Lynna [10]

Answer:

8x + 1/2 or 8x + 0.5

Step-by-step explanation:

-6x + 3 3/4 + 14x - 3.25

u can either convert the fraction to a decimal or convert the decimal into a fraction, i'm going to do the latter

-6x + 3 3/4 + 14x - 3 1/4

rearrange to make it easier, don't need to do this i'm just doing this for the sake of it

-6x + 14x + 3 3/4 - 3 1/4

8x + 2/4, simplify this

8x + 1/2

The decimal way if u want:

-6x + 3 3/4 + 14x - 3.25

-6x + 3.75 + 14x - 3.25

-6x + 14x + 3.75 - 3.25

8x + 0.5

6 0

3 years ago