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3 years ago

6

FREE POINTS BECAUSE IM EXITED FOR TOMAROW BECAUSE IM TRYING OUT FOR CHEER AND THEN SO I CAN CHEER FOR MY BROTHER WHEN HE PLAYS F

OOTBALL

2 answers:

kolbaska11 [484]3 years ago

6 0

Answer:

GOOD LUCK TO HIM AND YOU!! YOU GOT THIS!!! Be sure to have fun though.

algol [13]3 years ago

3 0

Thanks for the free points

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A manufacturing plant earned \$80$80dollar sign, 80 per man-hour of labor when it opened. Each year, the plant earns an addition

vagabundo [1.1K]

Answer:

$A(t)=80(1.05)^t$

Step-by-step explanation:

The manufacturing plant earned $80 per man-hour of labor when it opened

The plant earns an additional 5% for every additional man-hour t.

This can be modeled using the function:

$A(t)=P(1+r)^t$

where Initial Amount Earned, P=80

Rate of Increase, r=5%=0.05

Therefore, the function that models the amount earned at any time t is:

$A(t)=80(1+0.05)^t\\A(t)=80(1.05)^t$

3 0

4 years ago

Part 2: Identify the vertex, focus, and directrix of each. Then sketch the graph.

Andre45 [30]

Answer: $\bold{1.\quad \text{Vertex}}:(-3,-6)\qquad \text{Focus}:\bigg(-3,-\dfrac{17}{4}\bigg)\qquad \text{Directrix}:y=-\dfrac{19}{4}$

2. Vertex: (-5, 4) Focus: (-6, 4) Directrix: x = -4

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k or x = a(y - k)² + h

(h, k) is the vertex
p is the distance from the vertex to the focus
-p is the distance from the vertex to the directrix

$\bullet \quad a=\dfrac{1}{4p}$

1) y = (x + 3)² - 6 → a = 1 (h, k) = (-3, -6)

$a=\dfrac{1}{4p}\qquad \rightarrow \qquad 1=\dfrac{1}{4p} \qquad \rightarrow \qquad p=\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad =\dfrac{-18}{4}+\dfrac{1}{4}\\\\.\qquad = -\dfrac{17}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(-3,-\dfrac{17}{4}\bigg)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=\dfrac{-18}{4}-\dfrac{1}{4}\\\\.\qquad \quad y= -\dfrac{19}{4}$

****************************************************************************************

$2.\quad x=-\dfrac{1}{4}(y-4)^2-5\qquad \rightarrow \quad a=\dfrac{1}{4}\qquad (h, k)=(-5,4)$

$a=\dfrac{1}{4p}\qquad \rightarrow \qquad -\dfrac{1}{4}=\dfrac{1}{4p} \qquad \rightarrow \qquad p=-1\\\\\text{Focus = Vertex + p}\\\\.\qquad =-5+\ -1\\\\.\qquad = -6\qquad \rightarrow \qquad \text{Focus}=(-6,4)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=-5+\ -1\\\\.\qquad \quad y= -4$

7 0

4 years ago

Find the measure of the arc for abc

Luda [366]

Answer:

124

Step-by-step explanation:

360 - (90+146) = 124

5 0

3 years ago

What is the total perimeter of this figure? Express your answer in feet.

GarryVolchara [31]

We know that
perimeter of the figure=perimeter of semi circle+perimeter of rectangle
so
perimeter of semicircle=2*pi*r/2----> pi*r
diameter=6 yd
radius r=6/2----> r=3 yd

convert to ft
1 yd ------> is equal to 3 ft
3 yd-----> x
x=3*3----> x=9 ft
so
diameter=18 ft
radius=9 ft
perimeter of semicircle=pi*9----> 28.26 ft

perimeter of rectangle=18+15+15----> 48 ft

perimeter of the figure=28.26 ft+48 ft-----> 76.26 ft

the answer is
<span>76.26 ft</span>

6 0

3 years ago

Read 2 more answers

Which graph represents the solution set of the system of inequalities?

lidiya [134]

$y < \dfrac{2}{3}x\\\\y=\dfrac{2}{3}x\\\\for\ x=0\to y=\dfrac{2}{3}(0)=0\to(0,\ 0)\\\\for\ x=3\to y=\dfrac{2}{3}(3)=2\to(3,\ 2)\\\\y\geq-x+2\\\\y=-x+2\\\\for\ x=0\to y=-0+2=2\to(0,\ 2)\\\\for\ x=2\to y=-2+2=0\to(2,\ 0)$

$y < \dfrac{2}{3}x$

the dotted line. shadow under the line

$y\geq-x+2$

solid line. shadow above the line

Answer in the attachment (graph C).

8 0

3 years ago