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klemol [59]
3 years ago
6

FREE POINTS BECAUSE IM EXITED FOR TOMAROW BECAUSE IM TRYING OUT FOR CHEER AND THEN SO I CAN CHEER FOR MY BROTHER WHEN HE PLAYS F

OOTBALL
Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0

Answer:

GOOD LUCK TO HIM AND YOU!! YOU GOT THIS!!! Be sure to have fun though.

algol [13]3 years ago
3 0

Thanks for the free points

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What are three equivalent ratios to 2/20??
DiKsa [7]
2/20 = 1/10 = 3/30 = 4/40

so 3 equivalent ratios can be 1/10 (or 1:10), 3/30 (or 3:30), 4/40 (or 4:40)
6 0
3 years ago
A new youth activity center is being built in safe harbor. The perimeter of the rectangular playing field is 282 yards. The leng
lara [203]
Answer:
length=92yd
width=49yd

Step by step:
2l+2w=282
l=2w-6
Plug in l
2(2w-6)+2w=282
4w-12+2w=282
6w-12=282
6w=282+12
w=294/6
w=49
Then plug in w
2l+2(49)=282
2l+98=282
2l= 184
l=92
4 0
3 years ago
Find the value of x. Round to the nearest tenth. Please help!
Leviafan [203]

Answer: 4.5924 (4.6)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can you guys help please will mark brainliest answer.I need help on 24 and 28
frutty [35]
24) All percents are numbers with the decimal moved 2 to the right. So if you have 275%, move the decimal to the left twice to get a factor of 2.75. that means that the puppy is 2.75 times heavier at 4 months than it was at 2 months. Since you need the answer as a mixed fraction, your answer is;
2.75=2+\frac{3}{4}=2~\frac{3}{4}

28) If 6 of 75 trees are 30+ feet tall and you need to know how many are under, subtract 6 from 75 to get (75 - 6) = 69 trees under 30ft tall.
You're looking for the percent of trees under 30ft tall, so divide the number of trees <30ft by the total number of trees to get;
\frac{69}{75}= .92
Move the decimal 2 to the right to get 92%.
Your answer is that 92% of trees is under 30ft.
3 0
3 years ago
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
3 years ago
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