Question

-6g + 3g + 12 > -18

Answer 1

First of all, you can sum the two terms involving g on the left hand side:

$-6g + 3g + 12 > -18 \iff -3g + 12 > -18$

Subtract 12 from both sides:

$-3g > -30$

Divide both sides by -3: note that since we're dividing by a negative number, we must invert the inequality sign:

$g< 10$