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3 years ago

15

A cone has a radius of 6 inches and a height of 20 inches. What is the exact volume of the cone? A) 720π in3 B) 80π in3 C) 240π

in3 D) 120π in3

2 answers:

jasenka [17]3 years ago

8 0

The formula for finding volume of a cone is: (π · r² · h) ÷ 3

r = 6
6² = 6 × 6 = 36

h = 20

20 × 36 × π = 240π

Your answer is C. 240π

SIZIF [17.4K]3 years ago

3 0

The answer is c. 240π
V=πr² h/3 =π×6²× 20/3 ≈753.98224

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Hello!

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C = 2(36)π

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2 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

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Given:

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x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

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$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

Simplify the expression 6C2

iVinArrow [24]

Answer:

$^6C_2=15$

Step-by-step explanation:

Recall the formula:

$^nC_r=\frac{n!}{(n-r)!r!}$

We apply this formula to simplify $^6C_2$

This implies that:

$^6C_2=\frac{6!}{(6-2)!2!}$

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2 years ago