Question

A city is growing at the rate of 0.3% annually. If there were 3,278,000 residents in the city in 2015, find how many (to the nearest ten-thousand) are living in that city in 2021. Use y = 3,278,000(2.7)0.003t , where t represents the number of years since 2015.

Answer 1

The formula is
A=pe^rt
A ?
P 3,278,000
E constant, it equals 2.7
R 0.003
T 2,021−2,015=6 years

A=3,278,000×e^(0.003×6)
A=3,337,538

Answer 2

Answer:

3330448

Step-by-step explanation:

We must evaluate the population from 2015 to 2021 to the nearest ten-thousand. Using the following expression:

$y=3278000*(2.17)^0.003*t$

where t represents the number of years since 2015 and 2.17 is the logarithmic function e. The number of years since 2015 to 2021 is 7 years.Substitue t=7 into the expression:

$y=3278000*(2.17)^0.003*(7)=3278000*(1.016)=3330448$