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Lelechka [254]
3 years ago
9

A city is growing at the rate of 0.3% annually. If there were 3,278,000 residents in the city in 2015, find how many (to the nea

rest ten-thousand) are living in that city in 2021. Use y = 3,278,000(2.7)0.003t , where t represents the number of years since 2015.
Mathematics
2 answers:
ss7ja [257]3 years ago
3 0
The formula is
A=pe^rt
A ?
P 3,278,000
E constant, it equals 2.7
R 0.003
T 2,021−2,015=6 years

A=3,278,000×e^(0.003×6)
A=3,337,538
lys-0071 [83]3 years ago
3 0

Answer:

3330448

Step-by-step explanation:

We must evaluate the population from 2015 to 2021 to the nearest ten-thousand. Using the following expression:

y=3278000*(2.17)^0.003*t

where t represents the number of years since 2015 and 2.17 is the logarithmic function e. The number of years since 2015 to 2021 is 7 years.Substitue t=7 into the expression:

y=3278000*(2.17)^0.003*(7)=3278000*(1.016)=3330448

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3 years ago
Suppose that LMN is isosceles with base LN suppose that M
ira [324]

Given:

In an isosceles triangle LMN, LM=MN.

m\angle M=(3x+17)^\circ,m\angle L=(2x+36)^\circ

To find:

The measure of the angles L, M and N.

Solution:

In triangle LMN,

LM=MN                     (Given)

m\angle N=m\angle L=(2x+36)^\circ   (Base angles of an isosceles triangle are equal)

Now,

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On further simplification, we get

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The value of x is 13. Using this value, we get

m\angle L=(2(13)+36)^\circ

m\angle L=(26+36)^\circ

m\angle L=62^\circ

Similarly,

m\angle M=(3(13)+17)^\circ

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m\angle M=56^\circ

And,

m\angle N=m\angle L

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