There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.
Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 8 minus number of chairs which is required more which is 11.
Framing in equation form we get.
From equation 1 and equation 2 we can say that L.H.S is same.
So according to law of transitivity we get;
Combining like terms we get;
Using Subtraction and Addition property we get;
Now Using Division Property we will divide both side by 2.
Hence there are 7 chairs in each row length.
C. 4
14 + 13 - (23)
27 - 23
4
Answer: 14/25 = 56/100
11/20 = 55/100
14/25 > 11/20
Step-by-step explanation:
The least common multiple of 20 and 25 is 100.
(100 = 20*5, 25*4)
So we can take the common denominator 100.
14*4/25*4 =56/100. ∴14/25 = 56/100
11*5/20*5 =55/100. ∴11/20 = 55/100
56>55
∴56/100 > 55/100
∴14/25 > 11/20
Hope it's good;)
Answer:
D) 4
Step-by-step explanation:
−9 + 12 + (unknown) + −8 = −1
<em>Start by going through and testing each option</em>
−9 + 12 + 2 + −8 =
3 + 2 + −8 =
5 + −8 =
−3
−3 ≠ −1
<em>A) 2 is not possible.</em>
−9 + 12 + −2 + −8 =
3 + −2 + −8 =
1 + −8 =
−7
−7 ≠ −1
<em>B) </em>−<em>2 is not possible.</em>
−9 + 12 + −4 + −8 =
3 + −4 + −8 =
−1 + −8 =
−9
−9 ≠ −1
<em>C) </em>−4<em> is not possible.</em>
<em>From this, D is looking like the answer. But to be sure, test it.</em>
−9 + 12 + 4 + −8 =
3 + 4 + −8 =
7 + −8 =
−1
−1 = −1
<em>D) 4 is the answer.</em>
F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3