2x + 3x = _____??<br><br> help me pls

The Smith family goes out for lunch, and the price of the meal is $45.The sales tax on the meal is 6%, and the family also leave

Zinaida [17]

Answer:

$56.70

Step-by-step explanation:

45 x 6% = 2.7 Multiply price of meal with the percentage of sales tax

45 x 20% = 9 Multiply price of mean with the percentage of tip

$9 is the tip amount

$2.70 is the sales tax

$45 + $2.70 + $9 = $56.70. Add the price of the meal with the sales tax and tip amount to get the total cost of the meal.

3 0

3 years ago

How can I find the co-ordinatie of their point of intersection?

alisha [4.7K]

Combine the two equations so that it’s 2x+5=4x-1 and then subtract 2x from both sides. now it’s 5=4x-1 and add 1 to both sides. now is 6=4x 6 divided by 4 is 1.5 so that is the x value. now sub 1.5 as the x value into the first equation so it’s y=2(1.5)+5. you do the math and it’s y=8 (because 1.5 times 2 is 3 and 3+5 is 8) then your point is (1.5,8)

4 0

3 years ago

Divide 3ab by 2c in algebraic expression

Llana [10]

Answer:

$\frac{3ab}{2c}$

Step-by-step explanation:

An algebraic expression is an expression consists of constants, variables, and the algebraic operations: addition, subtraction, multiplication and division.

Given: algebraic expressions are $3ab,2c$ .

To divide: $3ab$ by $2c$

Solution:

$\frac{3ab}{2c}$

There are no common terms in numerator and the denominator.

So, answer is $\frac{3ab}{2c}$

8 0

3 years ago

146 Mathe Functional skills Level 1 Diagnostic

geniusboy [140]

Answer:

31

Step-by-step explanation:

56-25=31

6 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin

Sidana [21]

Answer:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

6 0

3 years ago

Read 2 more answers

2x + 3x = _____?? help me pls