Given the equation y - 4 = (x + 8) in point-slope form, identify the equation of the same line in standard form. (1 point)

Mathematics

1 answer:

Alecsey [184]4 years ago

3 0

Y-4=(x+8) = add4 to both sides of the equation, so y= x+8+4 then add like terms. Y=x+12 final answer.

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Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent th

oksian1 [2.3K]

Equation represents the difference in the number of foreign and domestic stamps Malik collected: X-34=y

equation represents the total number of stamps Malik collected:
212 = X-34-y
so,
245= X-Y

Situation :
Y= X-34
X-Y= 245

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P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
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$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
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x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
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\text{Solve: } x^2-2x -4=0\\\\
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x_2 =1-\sqrt{5}\\
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