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4 years ago

What is the inverse for y=-1/6x+17

Mathematics

1 answer:

Sphinxa [80]4 years ago

5 0

Answer:

all work is pictured and shown

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Angelo bought apples and bananas at the fruit stand. He bought 20 pieces of fruits and spent $11.50. Apples cost $0.50 and banan

Cerrena [4.2K]

<h2>Steps</h2>

So for this system, one equation will represent the number of fruit and the other equation will represent the combined total of the fruit. (Let x = apples and y = bananas):

$x+y=20\\0.5x+0.75y=11.50$

Next, I will be using the substitution method to remove one of the variables. To do this, firstly subtract both sides by y in the first equation:

$x=20-y\\0.5x+0.75y=11.50$

Next, since we know that x is equal to 20 - y, substitute it into the second equation and solve for y:

$0.5(20-y)+0.75y=11.50\\10-0.5y+0.75y=11.50\\10+0.25y=11.50\\0.25y=1.50\\y=6$

Now that we have the value of y, substitute it into either equation to solve for x:

$x+6=20\\x=14\\\\0.5x+0.75(6)=11.50\\0.5x+4.5=11.50\\0.5x=7\\x=14$

<h2>Answer</h2>

<u>In short, Angelo bough 14 apples and 6 bananas.</u>

8 0

4 years ago

Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

3 years ago

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What is 78.5 rounded to the nearest hundredth

AnnZ [28]

Answer:

There is no digit in the hundredths place, making this indeditable.

4 0

3 years ago

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What will be the 7th term in the sequence<br> Enter your answer as a fraction.

viktelen [127]

Answer:

1/32

Step-by-step explanation:

You plug 7 for n and solve in calculator.

7 0

3 years ago

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PLEASE HELP DESPERATE

bearhunter [10]

tan=sin/cos so tan=3/5/4/5=3/4

3 0

3 years ago

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What is the inverse for y=-1/6x+17​

What is the inverse for y=-1/6x+17