4 years ago

What is the inverse for y=-1/6x+17

Mathematics

1 answer:

Sphinxa [80]4 years ago

5 0

Answer:

all work is pictured and shown

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3 years ago

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Musya8 [376]

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B. $4\sqrt{3}-6$

Step-by-step explanation:

We have,

The first term of the series, $a=\sqrt{3}$ .

The common difference is given by, $r=\frac{\frac{-3}{2}}{\sqrt{3}}$ i.e. $r=\frac{-\sqrt{3}}{2}$ .

Since, the given series is an infinite series, then,

Sum of an infinite series = $\frac{a}{1-r}$

i.e. Sum the series = $\frac{\sqrt{3}}{1+\frac{\sqrt{3}}{2}}$

i.e. Sum the series = $\frac{2\sqrt{3}}{2+\sqrt{3}}$

i.e. Sum the series = $\frac{2\sqrt{3}}{2+\sqrt{3}}\times \frac{2-\sqrt{3}}{2-\sqrt{3}}$

i.e. Sum the series = $\frac{2\sqrt{3}\times (2-\sqrt{3})}{4-3}$

i.e. Sum the series = $4\sqrt{3}-6$

Thus, the sum of the series is $4\sqrt{3}-6$ .

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3 years ago

What is the inverse for y=-1/6x+17​

What is the inverse for y=-1/6x+17