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4 years ago

What is the inverse for y=-1/6x+17

Mathematics

1 answer:

Sphinxa [80]4 years ago

5 0

Answer:

all work is pictured and shown

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2 years ago

In triangle △JKL, ∠JKL is right angle, and KM is an altitude. JL=25 and JM=5, find KM.

d1i1m1o1n [39]

Answer:

KM = 15

Step-by-step explanation:

From the diagram, ΔJKL and ΔJKM are similar to each other because they share the same angle J and they are both right angle triangle. Therefore they are similar by AA property.

Since JL=25 and JM=5, JM = JL + JM= 25 + 5 = 30

Since ΔJKL and ΔJKM are similar to each other, therefore:

$\frac{JK}{JL}=\frac{JM}{JK}\\ Substituting:\\\frac{JK}{30}=\frac{5}{JK}\\JK^2=150\\JK=\sqrt{150}\\ \\From\ hypotenuse:\\JK^2=JM^2+KM^2\\Substituting:\\(\sqrt{150} )^2=5^2+KM^2\\150=25+KM^2\\KM^2=150-25=125\\KM=\sqrt{125}\\ KM=15$

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4 years ago

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jarptica [38.1K]

Answer:

Step-by-step explanation:

The slope of the line is zero because it is a horizontal line with no rise or fall.

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3 years ago

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If a line segment is perpendicular to another line segment, it is the bisector of that line segment.

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False. Perpendicular lines run beside each other not through each other.

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4 years ago

Solve this proportion: 1/c+5=2/3

Fittoniya [83]

$\frac{1}{c} +5=\frac{2}{3}\ \|\ subtract\ 5\ to\ both\ sides \\\\\frac{1}{c} =\frac{2}{3}-5\\\\\frac{1}{c} =\frac{2}{3}-\frac{15}{3}\\\\\frac{1}{c} = \frac{-13}{3}\\\\-13c=3\ \ | \ divide \ both \ sides\ by\ (-13)\\\\c=-\frac{3}{13}$

$\frac{1}{c+5} = \frac{2}{3} \\\\2(c+5) =3\\\\2c+10=3\ \ |\ subtract\ 10\ to\ both\ sides \\\\ 2c=3-10 \\\\2c=-7 \ \ | \ divide \ both \ sides\ by\ 2 \\\\c=-\frac{7}{2}\\\\c=-3.5$

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3 years ago

What is the inverse for y=-1/6x+17​

What is the inverse for y=-1/6x+17