Answer:

Step-by-step explanation:
To write the expression as a single logarithm, or condense it, use the properties of logarithms.
1) The power property of logarithms states that
. In other words, the exponent within a logarithm can be brought out in front so it's multiplied by the logarithm. This means that the number in front of the logarithm can also be brought inside the logarithm as an exponent.
So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

2) The product property of logarithms states that
. In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of
and
. Apply the property as seen below and find the final answer.

So, the answer is
.
Answer:
Step-by-step explanation:
Since; the density function diagrams were not included in the question; we will be unable to determine the best which depicts this problem.
However;
Let use X to represent the time required for the delivery.
Then X~N(3.8 ,0.8)
i.e
E(x) = 3.8
s.d(x) = 0.8
NOW; P(x>4) = P(X-3.8/0.8 > 4-3.8/0.8)
= P(Z > 0.25)
= 1-P(Z < 0.25)
=1 - Φ (0.25)
= 1 - 0.5987 ( from Normal table Φ (0.25) = 0.5987 )
= 0.4013
Thus; the probability a single delivery would take more than 4 hours is 0.4013
What is the z value corresponding to the interval boundary?
The z value is calculated as:


z = 0.25
<h2>
Answer:</h2><h2>D = 4</h2>
<h2>Hope this helps!!</h2>
2,8 meters than cuts it into 7 equal parts so each piece will be
2,8/7 = 0,4 meters
hope helped
Answer: 
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
d = kilograms of dark chocolate
m =kilograms of milk chocolate
So, her recipe calls for twice the amount of dark chocolate as milk chocolate.
Mathematically speaking:
m = 2d
She needs to buy 120 kg, of chocolate in total. So;
m + d = 120
The following system of equations represent the situation:

Feel free to ask for more if it´s necessary or if you did not understand something.