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Svet_ta [14]
4 years ago
11

Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.

Mathematics
1 answer:
pashok25 [27]4 years ago
5 0

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

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Crazy boy [7]
=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5

=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators

=(-4 * -4)/(5 * 5) * -3/50

=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50

=(16 * -3)/(25 * 50)
= -48/1250

simplify by 2
= -24/625 (or -0.0384)


ANSWER: -24/625 (or -0.0384)

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
REAL ANSWERS PLEASE AND NOT JUST FOR THE POINTS 20 EACH
Fed [463]
A+b=(-3n+2)+(5n-7)

=(5-3n)+(2-7)

=2n-5


Came up with the same answer as the first guy
4 0
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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