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timofeeve [1]
4 years ago
8

What does the prefix hepta mean

Chemistry
2 answers:
lesantik [10]4 years ago
6 0
Hepta is defined as seven. An example of the hepta prefix is a heptagon, a shape with seven sides.
ss7ja [257]4 years ago
5 0
The prefix hepta means 7
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A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it ne
irina1246 [14]

The question is incomplete, the complete question is;

A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it neared the pile, the magnet started attracting small pieces of iron from the pile. Which of these statements best describes the contents of the pile?

F. It is a homogeneous mixture of iron and sulfur.   G. It is a heterogeneous mixture of iron and sulfur.   H. It is a compound that contains both iron and sulfur.   I. It is a compound that can be separated by magnetism.

Answer:

G. It is a heterogeneous mixture of iron and sulfur.

Explanation:

A heterogeneous  mixture is one that does not have a uniform composition throughout.

We must recall that a mixture is any combination of substances that do not chemically react together and are separable by physical means.

Having said this, it is clear that I can separate the iron from sulphur by simple magnetic (physical) means. Hence,  it is a heterogeneous mixture of iron and sulfur.

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What is the frequency of a wave?
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Divide velocity by the wavelength.
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Is water denser than vinegar
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Vinegar is denser than water
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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
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