Question

An aluminium kettle weighs 1.05 Kg.

Answer 1

Answer:Explained

Explanation:

Given

mass of aluminium kettle($m_k$)=1.05 kg

(a)Heat capacity of the kettle=Heat capacity of Aluminium

$C_{Al}=0.9 J/gm-K$

(b)Heat is required to increase the temperature of this kettle from $23^{\circ} to 99 ^{\circ}$

$Q=m_kc_k\Delta T$

$Q=1.05\times 0.9\times 1000\times \left ( 99-23\right )$

Q=71.82 kJ

(c)If kettle contains water 1.25 L of water i.e. 1.246 kg of water then heat required to raise the temperature from 23 to 99

$Q=m_kc_k\left ( \Delta T\right )+m_wc_w\left ( \Delta T\right )$

$Q=1.05\times 0.9\times 1000\times \left ( 99-23\right )+1.246\times 4.184\times 1000\times \left ( 99-23\right )$

Q=71.82+396.20=468.028 kJ