80 student tickets and 30 adult tickets must be sold to reach a $700 raise.
Since the drama club is selling tickets to their play to raise money for the show's expenses, and each student ticket sells for $ 5 and each adult ticket sells for $ 10, and the auditorium can hold a maximum of 110 people and the drama club must make a minimum of $ 700 from ticket sales to cover the show's costs, to determine one possible solution the following calculation must be performed:
- 110 x 5 + 0 x 10 = 550
- (700 - 550) / (10 - 5) = 150/5 = 30
- 80 x 5 + 30 x 10 = 400 + 300 = 700
Therefore, 80 student tickets and 30 adult tickets must be sold to reach a $700 raise.
Learn more about maths in brainly.com/question/25901815
First we calculate the volume of the foundation:
Volume (V) = 20 ft * 12 ft * 4 in (1 ft / 12 in)
V = 80 ft^3
Since the cost is in cubic yard (yard^3) so convert:
V = 80 ft^3 * (1 yard^3 / 27 ft^3) = 2.963 yard^3
So the total cost is:
cost = ($125 / yard^3) * 2.963 yard^3
<span>cost = $370.37</span>
Answer:
Simplified= −x+9
Step-by-step explanation: