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2 years ago

a boy is older than his sister by 3 years five years ago, the ratio of their ages was 4 : 3 find his present.

Mathematics

2 answers:

pashok25 [27]2 years ago

8 0

B:S = 4x:3x
4x - 3x = 3
x = 3
They were 12 & 9.
Add 5 to that.
So he’s now 17 and she’s 14

AnnZ [28]2 years ago

8 0

Answer:

five years ago -- boy- x+3 years

sister --- x

ratio-- 4:3 so difference is 3 years

4-3-- 1 1--3

five years ago --- sister :3*3--9 brother : 4*3--12

present : sister 14 years and brother 17 years old

Step-by-step explanation:

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$\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}$

$\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}$

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

$\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}$

Now just compare the numerators to see which one is bigger.

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Step-by-step explanation:

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2 years ago

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max2010maxim [7]

Answer:

See below

Step-by-step explanation:

An invalid solution.

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ETC

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1 year ago

a boy is older than his sister by 3 years five years ago, the ratio of their ages was 4 : 3 find his present.​

a boy is older than his sister by 3 years five years ago, the ratio of their ages was 4 : 3 find his present.