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Katyanochek1 [597]
3 years ago
11

Which relationships could have a negative correlation? Select three options. 1.number of hours on video games and test scores 2.

speed of a car and minimum stopping distance 3.average running speed and total race time 4.adult’s head circumference and age 5.outside temperature and amount of a heating bill
Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

A C E........................ go for it

Step-by-step explanation:

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If a variable stands by itself, what is its coefficient?
Ludmilka [50]
The coefficient would be 1
before every variable, there is a one
So, x is equal to 1x
x+x is 2x
hope this helps:)
8 0
3 years ago
Read 2 more answers
Each morning, Jared needs 60 minutes to get ready for school. Kira needs 7/12 as much times as Jared. How many minutes does kiar
Fudgin [204]

Answer:

Kira takes 35 minutes to get ready for school.

Step-by-step explanation:

The time taken by Jared to get ready for school is, 60 minutes.

Time taken by Kira to get ready for school is \frac{7}{12} times as much as Jared needs.

Compute the time taken by Kira as follows:

Time taken by Kira =\frac{7}{12}\times60=35\ minutes

Thus, Kira takes 35 minutes to get ready for school.

3 0
3 years ago
This is adding linear equations:
Kipish [7]
1. -x-1
2. -10x+9
3. -3x+1
4. -4.8x-0.8
5. -1.25x-0.7
6. -6x-20
7. 10x+10
8. -x+16

You’re welcome
4 0
3 years ago
71.2% of 722.69 what is this​
Alex_Xolod [135]

Answer:

514.5552

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
I need help with pre calculus.
otez555 [7]

Question 1

<h3>Answer:  Choice A) -7</h3>

-----------------

Explanation:

To compute f(g(2)), we'll first need to find g(2).

Locate 2 in the x row. Then read straight down until you get to the g(x) row. You should find that g(2) = 4

This means f(g(2)) becomes f(4). We then repeat the same process as before. Locate 4 in the x row, read straight down til you get to the f(x) row to find that f(4) =  -9

Overall, we can say f(g(2)) = -9

We do the same set of steps to compute g(f(-1)). You should find that f(-1) = -1 and g(f(-1)) = g(-1) = -2

Lastly, we subtract the results we got:  

f(g(2)) - g(f(-1)) = -9 - (-2) = -9+2 = -7

==============================================

Question 2

<h3>Answer: Choice B)  0</h3>

-----------------

Explanation:

If you were to graph each equation, you should get what you see below.

The red and blue curves do not intersect in any way. We need an intersection point to have a solution. Because there are no intersections, we don't have any solutions. The system is considered inconsistent.

==============================================

Question 3

<h3>Answer: Choice B</h3><h3>-2x^2+250x-2000</h3>

-----------------

Explanation:

x = number of scooters made and sold

Each scooter costs $150 to make. If you made x of them, then it costs 150x dollars. Then tack on the fixed cost of $2000 to get the expression 150x+2000

The cost function is C(x) = 150x+2000. We'll subtract this from the revenue function R(x) to get the profit P(x)

\text{Profit} = \text{Revenue} - \text{Cost}\\\\P(x) = R(x) - C(x)\\\\P(x) = (400x-2x^2) - (150x+2000)\\\\P(x) = 400x-2x^2-150x-2000\\\\P(x) = -2x^2+250x-2000\\\\

==============================================

Question 4

<h3>Answer: Choice B</h3>

\left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}

-----------------

Explanation:

g(x) = \frac{1}{x+1}\\\\g(f(x)) = \frac{1}{f(x)+1}\\\\g(f(x)) = \frac{1}{x^2+x-3+1}\\\\g(f(x)) = \frac{1}{x^2+x-2}\\\\g(f(x)) = \frac{1}{(x+2)(x-1)}\\\\(g\circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\

I started with the outer function g(x) and replaced each x with f(x) in the second step. Then I plugged in f(x) = x^2+x-3 and simplified. Factoring the denominator is helpful to determine where the denominator becomes zero. Specifically, it happens when x = -2 and x = 1. These x values must be kicked out of the domain to avoid a division by zero error.

So we start off with the real number line, and poke holes at x = -2 and x = 1.

The notation x \in \mathbb{R} means x is a real number. Then we tack on x \ne -2, x \ne 1

Overall, the domain is \left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}

Let's see what happens if we tried plugging x = -1 into this composite function:

(g \circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\(g \circ f)(-1) = \frac{1}{(-1+2)(-1-1)}\\\\(g \circ f)(-1) = \frac{1}{(1)(-2)}\\\\(g \circ f)(-1) = \frac{1}{-2}\\\\(g \circ f)(-1) = -0.5\\\\

We don't get a division by zero error, so x = -1 is allowed. The same can be said about any other x value as long as it's not -2 and not 1 either.

4 0
2 years ago
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