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ollegr [7]
3 years ago
7

Kevin can travel 22 1/3 hour.what is his average speed in miles per hour

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0
66 mph and if it was 22 1/2 like my question was it would be 67.5 mph.
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Y=y = 2x -4 when x= 2
Dominik [7]
Y would equal 0. 2x2=4 and 4-4=0.
7 0
3 years ago
I need help on solving these types of geometry problems! Teacher said the answer is 7 but I have to show work. Thank you!
Nikolay [14]

The vertex where the two triangles touch forms a pair of vertical angles, so that the angles on opposites sides of the vertex are congruent. You're shown that two legs of both triangles are congruent. All this tells you that the two triangles are isosceles, and furthermore that they are similar because of the congruence of their "base" angles.

This means

82^\circ=m\angle 2

\implies82=10x+12

\implies10x=70

\implies\boxed{x=7}

4 0
3 years ago
Your goal is to save $50. So far, you have saved $34. How much more money do you need to save? Write your answer as a rational n
belka [17]

Answer:

You need to save $16 more dollars.

Step-by-step explanation:

If you add 16 to 34 you get 50.

3 0
3 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
4 years ago
What is another way this expression can be written 0.7×0.4
KiRa [710]

Answer:

7/10*4/10

Step-by-step explanation:

7/10 and 4/10 are both just the fraction forms of the decimal so it should work

8 0
3 years ago
Read 2 more answers
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