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3 years ago

Help me please!!!!!!

Mathematics

1 answer:

NARA [144]3 years ago

4 0

Its D. you can eliminate others.

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A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

2 years ago

Solve x^2+32=0<br> Please solve step by step

erik [133]

Answer:

......

...............................

5 0

3 years ago

I NEED HELP ASAP PLEASE!

dusya [7]

Answer:

The length of AC = 4 and the length of A'C' = 1 so the scale factor is 1/4.

8 0

3 years ago

Oscar needs to purchase soft drinks for a staff party. He is

PilotLPTM [1.2K]

Answer:

sorry getting points

Step-by-step explanation:

4 0

2 years ago

Feliz is looking at a cyclic quadrilateral EFGH. He says, "I'm not convinced that opposite

azamat

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

<h3>How to find angles of cyclic quadrilateral?</h3>

A cyclic quadrilateral is inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore,

∠F + ∠H = 180°

∠G + ∠E = 180°

Hence, if we moved ∠G to a different spot on the circle, angle FGH would change but angle FEH will also change to make the two opposite angles supplementary.

Therefore, Felix was wrong.

learn more on cyclic quadrilateral here: brainly.com/question/21208662

#SPJ1

5 0

2 years ago