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Anvisha [2.4K]
3 years ago
10

In Olongapo City, a bump car ride costs

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0
Solve for n in 270=120 + n*10. 120 gives you first 30 minutes and n is the number of additional 10 minutes you ride. In this case you ride for 30+n*10 minutes. n = (270-120)/10 = 15. So the total time is 30+15*10 = 180 minutes. Or three hours!! That’s a lot of bumper cars!!
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PLEASE help with number 5!!
LUCKY_DIMON [66]

Answer:

5/12

Step-by-step explanation:

1. Convert 1/4 to 3/12, then convert 1/3 to 4/12

2. Then add 3/12 and 4/12 together, which would be 7/12

3. Then subtract 12/12 by 7/12 which would be 5/12

                                         So, 5/12 is your answer.

                                                Hope this helps

8 0
3 years ago
Need help ASAP
xz_007 [3.2K]

Answer:

Alternate Interior angles! ? = 50 :)

Step-by-step explanation:

They are both interior, and they are alternate, so the type of angle pair is an alternate interior angles pair!

Relationship: They are congruent to each other!

They are also both equal! :)

7 0
3 years ago
What is the area of the triangle shown below? 13 13 10
Firdavs [7]

Answer: 60 units^2

Step-by-step explanation:

6 0
3 years ago
How do i solve for a variable in an equation?
Sati [7]
You solve for a variable in an equation by taking the variable to one side of the equation and other terms to the other side of the equation using arithmetic properties.
3 0
4 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
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