Question

Rewrite square root of -49 -4 in complex number notation please help

Answer 1

Note that if $i^2=-1$ than $i=\sqrt{-1}$,

Also note that $\sqrt{ab}=\sqrt{a}\sqrt{b}$

So we have,

$\sqrt{-49}=\sqrt{-1}\sqrt{49}=\boxed{7i}$

and,

$\sqrt{-4}=\sqrt{-1}\sqrt{4}=\boxed{2i}$

Hope this helps.

r3t40