All categories

3 years ago

There are 7 males and 5 females and we need to select 4 different people. how many ways can we select 4 people?

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

$\displaystyle \binom{12}{4}=\dfrac{12!}{4!8!}=\dfrac{9\cdot10\cdot11\cdot12}{2\cdot3\cdot4}=495$

You might be interested in

Suzanne in Barry each by four equals sized bagels. They divide the bagels equally among themselves and three other friends. How

grandymaker [24]

Number of people = 5 (Suzanne, Barry, and 3 friends)
Number of bagels = 4

4 bagels divided between 5 people is 4/5.

6 0

3 years ago

Read 2 more answers

(0,0) and (-4,-5) in point slope form (please show work if possible)

Kaylis [27]

I think formula is y2-y1 divided by x2-x1 so if im correct
-5/-4

4 0

3 years ago

Read 2 more answers

Eric bought apples and oranges for $7.75. He paid $2.35 for all the apples

Kruka [31]

Answer:

He bought 12 oranges.

Step-by-step explanation:

Key words: "ALL the apples" "EACH orange."

7.75-2.35= 5.4

5.4/0.45= 12

8 0

3 years ago

20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS QUESTION !!

dezoksy [38]

Answer:

$(8m - 2)^{2}$

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers