Answer:
c.
hope it helps :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
the expression will be
n-35
First, you divide 4 by 2 before you subtract them by 5 using BODMAS, or BIDMAS.
4 ÷ 2 = 2
5 - 2 = 3
3 is your answer
Answer:
18 ft
Step-by-step explanation:
Answer:
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.95}{2} = 0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.95%7D%7B2%7D%20%3D%200.025)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 1.96](https://tex.z-dn.net/?f=z%20%3D%201.96)
Now, find the margin of error M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 1.96\frac{20}{\sqrt{125}} = 3.51](https://tex.z-dn.net/?f=M%20%3D%201.96%5Cfrac%7B20%7D%7B%5Csqrt%7B125%7D%7D%20%3D%203.51)
The lower end of the interval is the sample mean subtracted by M. So it is 91 - 3.51 = 87.49
The upper end of the interval is the sample mean added to M. So it is 91 + 3.51 = 94.51
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.