All categories

3 years ago

H(x) = 2x^2 =4; Find h(-10)

Mathematics

1 answer:

bogdanovich [222]3 years ago

3 0

For this case we have the following function:

$h (x) = 2x ^ 2 + 4$

We must find the value of the function when x = -10

So, replacing we have:

$h (-10) = 2 (-10) ^ 2 + 4\\h (-10) = 2 (100) +4\\h (-10) = 200 + 4\\h (-10) = 204$

Thus, the value of the function is 204 when x = -10

Answer:

$h (-10) = 204$

You might be interested in

M is the midpoint of AN, A has coordinates (-6, -6) and M has coordinates (1, 2). Find the coordinates of N.

Cloud [144]

The midpoint, M, of points A and N is (8,10) because;
Point A is (-6,-6) which has a slope of 8/7 (rise/run) with M, (1,2). So, if 8/7 is repeated/ added to M, it will be point N.
1+7=8 (run/x)
2+8=10 (rise/y)
Put x and y together to get (8,10).
N= (8,10).

5 0

2 years ago

Will mark brainliest

Harrizon [31]

Answer:

C : 0.167

Step-by-step explanation:

Have a nice day

8 0

3 years ago

Where does the last one go???

Nostrana [21]

Answer:

is goes to ¨¨not a function¨¨

Step-by-step explanation:

8 0

3 years ago

Can you pls help me with this?☺️<br>thank you ☺️<br>

den301095 [7]

12. MORT

13. MNR

14. SDT

15. MOSR

4 0

2 years ago

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

3 years ago