You are given a cone with width 2 inches and height 3 inches, and a cylinder with width 2 inches and height 7 inches. The volume of the cone is 3.14 cubic inches and the cylinder is 11 cubic inches.
You find the overall change in temperature by adding them together.
-8 would be from were is decreased 8 degrees and +8 would be from where it increased 8 degrees
Like: -8+8=0
Step-by-step explanation:
I think, he made a mistake because the exponents have different values but then if you'll look at his results, he just wrote the same thing. If you want, you could post the original problem, and I'll solve it for you :)
Answer:
C. y₂ = (1 + (t/n))²
Step-by-step explanation:
yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)
yₙ₊₁ = yₙ + Δt yₙ
yₙ₊₁ = yₙ + (t/n) yₙ
When n=0:
y₁ = y₀ + (t/n) y₀
y₁ = 1 + (t/n)
When n=1:
y₂ = y₁ + (t/n) y₁
y₂ = 1 + (t/n) + (t/n) (1 + (t/n))
y₂ = 1 + (t/n) + (t/n) + (t/n)²
y₂ = 1 + 2(t/n) + (t/n)²
y₂ = (1 + (t/n))²
The answer is 6/48. You would multiply 3/8 by 1/3 across and get 3/24,then you multiply 3/24 by 2 and get 6/48
