H(x) = 2x^2 =4; Find h(-10)

Mathematics

1 answer:

bogdanovich [222]3 years ago

3 0

For this case we have the following function:

$h (x) = 2x ^ 2 + 4$

We must find the value of the function when x = -10

So, replacing we have:

$h (-10) = 2 (-10) ^ 2 + 4\\h (-10) = 2 (100) +4\\h (-10) = 200 + 4\\h (-10) = 204$

Thus, the value of the function is 204 when x = -10

Answer:

$h (-10) = 204$

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