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3 years ago

Largest number you can make using 1 3 5 4 7

Mathematics

2 answers:

Mariana [72]3 years ago

4 0

75431? I think it is becuz I did it in greatest to smallest

Aloiza [94]3 years ago

3 0

I believe that the largest number that can be made using the scheme would be to simply turn it backwards, if thats not the case you can start with the 7 and add anything thats second biggest for the effect if it's going to be a 10's place number, such as 75, if your goal is bigger you can reach 75413

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ashton is saving money to buy a new bike. he needs $120 but has only saved 60% so far. How much more money does Ashton need to b

Tasya [4]

Ashton has saved: 60% of $120=(60/100)*$120=(60*$120)/100=$72
Ashton need to buy the bike=$120-$72=$48

He needs to buy the bike=$48

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3 years ago

2x + 3y = 12<br> Complete the missing value in the solution to the equation.

Alja [10]

Answer:

x= 6- 3y/2 y= 4- 2x/3

Step-by-step explanation:

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3 years ago

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The ratio of girls to boys in grade 6 was 3:2 at Lincoln middle school last year. There were 60 kids in grade 6. How many in gra

olasank [31]

Answer:

40 girls 20 boys i think / guess

Step-by-step explanation:

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2 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

Mr. Design is covering rectangular pieces of plywood with fabric to create a wall hanging. Each piece has an area of 12 3/4 squa

ExtremeBDS [4]

6 inches
6 1/14 inches
Since area is defined as length multiplied by width, this is a simple matter of division. I suspect this problem is more a matter of handling fractions, so to make things easier, convert the fractions to improper fractions in order to do the math, then convert to proper fractions after you've gotten the result. Since the area of each rectangle is 12 3/4, multiply 12 by 4 and then add 3 to get 51/4 as the area. Doing the same for the values 2 1/8 and 2 1/10 gives sizes of 17/8 and 21/10 for the widths respectively. So
51/4 / 17/8 = 51/4 * 8/17 = 408/68 = 6/1 = 6
51/4 / 21/10 = 51/4 * 10/21 = 510/84 = 85/14 = 6 1/14

3 0

3 years ago