d or c________________________
Step-by-step explanation:
vvv.
Answer:
28, 30, 32
Step-by-step explanation:
Three consecutive even numbers are three even numbers that are next to each other. For example, 2, 4 and 6 would be 3 consecutive even numbers.
With this sort of problem, you want to try to let each number be equal to one thing and then construct the same number of equations as you have variables:
Let's let,
Integer 1 = X
Integer 2 = Y
Integer 3 = Z
X + Y + Z = 90
We also know, that
Y = X + 2
And that
Z = X + 4
Now, we can sub these equations into the first equation. We do this so that we have everything represented as the same variable.
90 = X + (X+2) + (X+4)
90 = 3X + 6
84 = 3X
28 = X
So, the numbers are 28, 30 and 32
Answer:
see below
Step-by-step explanation:
a. Has a slope of 2 and passes through (10,17)
Using the slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = 2x+b
Substitute the point into the equation
17 = 2(10)+b
17 = 20+b
Subtract 20 from each side
17-20 =b
-3 =b
y = 2x-3
b. passes through (1,-4) and (2,-5)
First find the slope
m= (y2-y1)/(x2-x1)
= (-5- -4)/(2-1)
= (-5+4)/(2-1)
= -1/1
= -1
Using the slope intercept form
y = -x+b
Substitute a point into the equation
-4 = -1(1) +b
-4 = -1+b
Add 1 to each side
-3 = b
y = -x+3
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Hey there!!
Scientific notation for 0.0765 is
... 7.65 × 10^-2
Hope my answer helps!!