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otez555 [7]
3 years ago
5

The length of a rectangle is three times its width. If the area of the rectangle is 192 ft^2, find its perimeter

Mathematics
2 answers:
allochka39001 [22]3 years ago
6 0
Lets x = width
length = 3x

A = length times width
A = x * 3x
192 = 3x^2
192/3 = x^2
64 = x^2
8 = x

so width = 8
length = 3x = 3(8) = 24

P = 2(L + W)
P = 2(24 + 8)
P = 2(32)
P = 64

answer
P = 64 feet
Blababa [14]3 years ago
3 0
Answer: 64 feet.

Explanation:
Perimeter formula: 2l + 2w
Area formula: l•w
Length = 3w
Area = 192 ft^{2}
192 = (3w) • w 
192 = 3w^{2}
192 ÷ 3 = 3w^{2} ÷ 3
64 = w^{2} 
\sqrt{64} = \sqrt{ w^{2} }
8 = w 

Width = 8
Length = 3(8) = 24 
Perimeter = 2(24) + 2(8) = 64 feet.

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