The length of a rectangle is three times its width. If the area of the rectangle is 192 ft^2, find its perimeter

2 answers:

6 0

Lets x = width
length = 3x

A = length times width
A = x * 3x
192 = 3x^2
192/3 = x^2
64 = x^2
8 = x

so width = 8
length = 3x = 3(8) = 24

P = 2(L + W)
P = 2(24 + 8)
P = 2(32)
P = 64

answer
P = 64 feet

Blababa [14]3 years ago

3 0

Answer: 64 feet.

Explanation:
Perimeter formula: 2l + 2w
Area formula: l•w
Length = 3w
Area = 192 ft $^{2}$
192 = (3w) • w
192 = 3 $w^{2}$
192 ÷ 3 = 3 $w^{2}$ ÷ 3
64 = $w^{2}$
$\sqrt{64}$ = $\sqrt{ w^{2} }$
8 = w

Width = 8
Length = 3(8) = 24
Perimeter = 2(24) + 2(8) = 64 feet.

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