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garri49 [273]
3 years ago
14

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics
2 answers:
mojhsa [17]3 years ago
7 0
The answer would be b
Mariana [72]3 years ago
5 0

Answer:

B or A

Step-by-step explanation:

got it right on a test a year ago

(is probably B though.)

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6. Which rational number is equivalent to 0.72?​
goldenfox [79]

Answer:

18/25

Step-by-step explanation:

0.72 as a fraction equals 72/100

5 0
3 years ago
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Consider the matrix A. A = 1 0 1 1 0 0 0 0 0 Find the characteristic polynomial for the matrix A. (Write your answer in terms of
dusya [7]

Answer with Step-by-step explanation:

We are given that a matrix

A=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]

a.We have to find characteristic polynomial in terms of A

We know that characteristic equation of given matrix\mid{A-\lambda I}\mid=0

Where I is identity matrix of the order of given matrix

I=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

Substitute the values then, we get

\begin{vmatrix}1-\lambda&0&1\\1&-\lambda&0\\0&0&-\lambda\end{vmatrix}=0

(1-\lambda)(\lamda^2)-0+0=0

\lambda^2-\lambda^3=0

\lambda^3-\lambda^2=0

Hence, characteristic polynomial =\lambda^3-\lambda^2=0

b.We have to find the eigen value  for given matrix

\lambda^2(1-\lambda)=0

Then , we get \lambda=0,0,1-\lambda=0

\lambda=1

Hence, real eigen values of for the matrix are 0,0 and 1.

c.Eigen space corresponding to eigen value 1 is the null space of matrix A-I

E_1=N(A-I)

A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&-1\end{array}\right]

Apply R_1\rightarrow R_1+R_3

A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]

Now,(A-I)x=0[/tex]

Substitute the values then we get

\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0

Then , we get x_3=0

Andx_1-x_2=0

x_1=x_2

Null space N(A-I) consist of vectors

x=\left[\begin{array}{ccc}x_1\\x_1\\0\end{array}\right]

For any scalar x_1

x=x_1\left[\begin{array}{ccc}1\\1\\0\end{array}\right]

E_1=N(A-I)=Span(\left[\begin{array}{ccc}1\\1\\0\end{array}\right]

Hence, the basis of eigen vector corresponding to eigen value 1 is given by

\left[\begin{array}{ccc}1\\1\\0\end{array}\right]

Eigen space corresponding to 0 eigen value

N(A-0I)=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]

(A-0I)x=0

\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0

\left[\begin{array}{ccc}x_1+x_3\\x_1\\0\end{array}\right]=0

Then, x_1+x_3=0

x_1=0

Substitute x_1=0

Then, we get x_3=0

Therefore, the null space consist of vectors

x=x_2=x_2\left[\begin{array}{ccc}0\\1\\0\end{array}\right]

Therefore, the basis of eigen space corresponding to eigen value 0 is given by

\left[\begin{array}{ccc}0\\1\\0\end{array}\right]

5 0
3 years ago
Kenny has $1,400 in the bank. He earns $150 every week at his afterschool job. What is the rate of change for the scenario descr
stiks02 [169]
Rate of change would be 150.
6 0
3 years ago
The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw
shusha [124]
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball  
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>

</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in

the answer is
4.23 in
3 0
4 years ago
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Which statements about the graph of the function f(x) = –x2 – 4x 2 are true? check all that apply.
alekssr [168]
The statements that agree with the graph of the equation are as follows:

<span>4.the function is decreasing over the interval (−4, ∞). 

</span><span>1.the domain is {x|x ≤ –2}. 

I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions.
</span>
8 0
4 years ago
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