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Anon25 [30]
3 years ago
10

Need Help Please Easy

Mathematics
2 answers:
Serggg [28]3 years ago
6 0

Answer:

maybe re upload it with the naswer choices in the picture bc idk without them haha

Step-by-step explanation:

devlian [24]3 years ago
4 0

Answer:

i cant see the answer choices send them to me and ill answer in the comments

Step-by-step explanation:

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Number 47 step by step
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Second step.

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8 0
3 years ago
Dave drove to his friends house and back. It took one hour longer to go there than it did to come back. The average speed on the
mamaluj [8]

Remark

You know the most about the trip on the way back and the total of the two trips.

Way Back

r = 30 mph

d = distance traveled

t = t - 1 where t = the time to go there which we know nothing about

Total Distance

2d = 25 mph * (t + t - 1)

2d = 25 * (2t - 1)

2d = 50t  - 25                 Divide by 2

2d = 50t/2 - 25/2

d = 25t - 12.5

Equation coming back

d = 30*(t - 1)

d = 30t - 30

Comment

Since the distances are the same, equate them.

Solution

25t - 12.5 = 30t - 30                     Subtract 25t from both sides

25t - 25t -12.5 = 30t - 25t - 30   Combine like terms

-12.5 = 5t - 30                              Add 30 to both sides

-12.5 + 30 = 5t - 30 + 30             Combine

17.5 = 5t                                       Divide by 5

17.5/5 = t                                      Divide and Switch

t = 3.5

t is the time going there

t - 1 is the time coming back

Total time = 2*t - 1 = 2*3.5 - 1 = 6

The total time is 6 hours.   Answer


3 0
3 years ago
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