A zoo had 11,287 visitors one weekend,

1 answer:

3 0

11,287-5,159 (find the difference) = 6128

I understand they want you to use rounding. I’m not sure whether that is before or after the finding the difference but I would round it up to the nearest 100.

So the two possible answers I would give are

6,100 or 6100

Now that I’ve done both I see that it doesn’t really matter

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The television show 50 Minutes has been successful for many years. That show recently had a share of 29, meaning that among the

BigorU [14]

Answer:

(a) P (none) = 0.005873

(b) P ( at least one household ) = 0.9941

(c) P ( at most one household ) = 0.9960

(d) not wrong

Step-by-step explanation:

Given data

probability P = 29% = 0.29

no of sample n = 15

tv show X = 50

to find out

the probability that none of the households

the probability that at least one household

the probability that at most one household

If at most one household is tuned to 50 Minutes, does it appear that the 19% share value is wrong

solution

the probability that none of the households is tuned to 50 Minutes is

P (none) = 10C0 × $P^{0}$ × $(1 - 0.29)^{15}$

P (none) = $(0.71)^{15}$

P (none) = 0.005873

and the probability that at least one household is tuned to 50 Minutes is

P ( at least one household ) = 1 - P(none)

P ( at least one household ) = 1 - 0.005873

P ( at least one household ) = 0.9941

the probability that at most one household is tuned to 50 Minutes is

P ( at most one household ) = P (none) + P (x=1)

P ( at most one household ) =0.9941 + 10C1 × $(0.23)^{1}$ × $(0.71)^{14}$

P ( at most one household ) = 0.9960

and in last part If at most one household is tuned to 50 Minutes it appear that the 19% share value is not wrong

because P( at most one household ) is not zero

8 0

3 years ago

a person goes from a sauna at 115°F to an out side temperature of -30°F. what is the change in temperature?

Oksana_A [137]

Whenever you're interested in computing the (absolute) difference between two values of a certain variable, you have to subtract the final value and the initial value. This is often written as delta:

$\Delta x = x_{\text{final}} - x_{\text{initial}}$