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Tems11 [23]
4 years ago
7

The population of a small town in Maryland has grown at a constant rate over the last ten years. In 1998, the population was 305

people. If the population increased by 15% each year, what is the population in 2008? A. 350 people B. 457 people C. 1,233 people D. 3,507 people
Mathematics
1 answer:
Andreyy894 years ago
4 0
A=P(1+r)^t

A=305(1+.15)^10

A= 1233
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1111111111!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
FinnZ [79.3K]

Answer:

1 1/2 or 3/2

Step-by-step explanation:

8 1/4 divided by 5 1/2

Convert to improper fraction

33/4 divided by 11/2=66/44

Simplify this to get 1 1/2 or 3/2

6 0
3 years ago
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Answer:

F

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3 years ago
A man walked steadily from 11 am to 2.30 pm at 5 kilometres per hour how far did he walk!
matrenka [14]

Answer:

Distance traveled 17.5 kilometers

Step-by-step explanation:

We can use the following equation to find the distance traveled,

Distance traveled = Speed * Time

First we need to find the total time he walked = 2.30 p.m. - 11.a.m.

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3 0
3 years ago
Log3/5 25/9=x-2 ? algebra 2
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6 0
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Dmitriy789 [7]

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The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

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\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 6 + 19}\times6 \\ T_{20\text{ }}\text{ = 6 + 114} \\ T_{20\text{ }}\text{ = 120} \end{gathered}

2) 3,6,9,12

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 3, d = 3

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 3 + 19 }\times3 \\ T_{20\text{ }}\text{ = 3 + 57} \\ T_{20\text{ }}\text{ = 60} \end{gathered}

3) 1,5,9,13

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 1, d = 4

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 1 + 19 }\times4 \\ T_{20\text{ }}\text{ = }1\text{ + 76} \\ T_{20\text{ }}\text{ = }77 \end{gathered}

5 0
1 year ago
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