A man walked steadily from 11 am to 2.30 pm at 5 kilometres per hour how far did he walk!
1 answer:
Answer:
Distance traveled 17.5 kilometers
Step-by-step explanation:
We can use the following equation to find the distance traveled,
Distance traveled = Speed * Time
First we need to find the total time he walked = 2.30 p.m. - 11.a.m.
= hours
Now we can substitute the values to the equation,
Distance traveled = kilometers per hour *
hours
= kilometers
= 17.5 kilometers
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Answer:
Step-by-step explanation:
We have the system of equations:
We can convert this to a matrix. In order to convert a triple system of equations to matrix, we can use the following format:
Importantly, make sure the coefficients of each variable align vertically, and that each equation aligns horizontally.
In order to solve this matrix and the system, we will have to convert this to the reduced row-echelon form, namely:
Where the (x, y, z) is our solution set.
Reducing:
With our system, we will have the following matrix:
What we should begin by doing is too see how we can change each row to the reduced-form.
Notice that R₁ and R₂ are rather similar. In fact, we can cancel out the 1s in R₂. To do so, we can add R₂ to -2(R₁). This gives us:
Now, we can multiply R₂ by -1/5. This yields:
From here, we can eliminate the 3 in R₃ by adding it to -3(R₁). This yields:
We can eliminate the -5 in R₃ by adding 5(R₂). This yields:
We can now reduce R₃ by multiply it by -1/4:
Finally, we just have to reduce R₁. Let's eliminate the 2 first. We can do that by adding -2(R₂). So:
And finally, we can eliminate the second 1 by adding -(R₃):
Therefore, our solution set is
And we're done!