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3 years ago

What is divided 89 into 4356?

Mathematics

1 answer:

mars1129 [50]3 years ago

8 0

80 divided into 4356 should be around 48.94

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An angle of -210 degree is in standard position. What are the coordinates of the point at which the terminal side intersects the

Lunna [17]

Answer:

( - $\sqrt{3}$ /2 , -1/2)

Step-by-step explanation:

-210 degrees in standard position corresponds to an angle in the 3rd quadrant 30 degrees below the negative x-axis

The hypotenuse of the triangle here is 1, and we want the coordinates.

_______________________(0,0)

|(x = -root(3)/2)

| (y = -1/2)

4 0

3 years ago

You paint 1 2 12 wall in 1 4 14 hour. At that rate, how long will it take you to paint one wall

Rudiy27

Ok. <span>well the answer 1/2 the hour you paint 1/2 in 1/4 so add 1/2+1/2=1 so it is 2 so 1/4+1/4 </span>

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3 years ago

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a fitness center offers yoga for $10 per class and sells yoga mats for 19.95. A person paid a total cost f $139.95 to the fitnes

Ne4ueva [31]

10x + 19.95 = 139.95

Subtract 19.95 from both sides
10x =130.00
Divide both sides by 10

X = 13

13 classes

6 0

2 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

A class quiz has 5 True/False questions. The correct answers are T, T, F, F, and T, in that order. John answered the questions r

rosijanka [135]

Answer: 1/2

Step-by-step explanation:

I got it right.

3 0

3 years ago

Read 2 more answers