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topjm [15]
3 years ago
10

Let's say we have a triangle with sides called a, b, and c, and that b is the base. Our triangle has a height that we'll call h.

If a = 11 inches, and b = 3 inches, and c = 11 inches, and h = 10.89 inches, what is the area of this triangle in square inches? Round your answer to the nearest hundredths place. 16.3 16.34 21.9 21.89
Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

16.34 square inches.

Step-by-step explanation:

Given:

Base of triangle, b = 3 inches

Height of triangle, h = 10.89 inches

Question asked:

What is the area of this triangle in square inches?

Round your answer to the nearest hundredths place .

Solution:

As we know,

Area\ of\ triangle =\frac{1}{2} \times base\times height

                           =\frac{1}{2} \times3\times10.89\\\\ =\frac{32.67}{2} \\\\ =16.335

As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.

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The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

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$\frac{dP(t)}{dt}=200e^{0.02t}$  in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

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$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

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So in 1995,

$P=P_0e^{kt}$

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In 2000,

$P=10,000e^{0.02(10)}$

   =12,214

Therefore, the change in the population between 1995 and 2000 = 1,163.

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