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topjm [15]
3 years ago
10

Let's say we have a triangle with sides called a, b, and c, and that b is the base. Our triangle has a height that we'll call h.

If a = 11 inches, and b = 3 inches, and c = 11 inches, and h = 10.89 inches, what is the area of this triangle in square inches? Round your answer to the nearest hundredths place. 16.3 16.34 21.9 21.89
Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

16.34 square inches.

Step-by-step explanation:

Given:

Base of triangle, b = 3 inches

Height of triangle, h = 10.89 inches

Question asked:

What is the area of this triangle in square inches?

Round your answer to the nearest hundredths place .

Solution:

As we know,

Area\ of\ triangle =\frac{1}{2} \times base\times height

                           =\frac{1}{2} \times3\times10.89\\\\ =\frac{32.67}{2} \\\\ =16.335

As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.

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x + y = - 5

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Given

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3 years ago
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ohaa [14]

Answer:

x > 3

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Step-by-step explanation:

Given the inequality statement: 4x - 5 > 7,

The goal is to isolate x and find its solution.

Start by adding 5 to both sides:

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The solution can also be expressed in the following interval notation:

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5 0
2 years ago
What is the approximate value of k?
lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

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From the law of sines

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sin(120) =  k *  (  sin(20)/2) )                (multiply both sides by "k")

k = sin(120)/  (   sin(20)/2)                    (divide both sides by sin(20)/2)

k =  (0.866) /  ( 0.171) =  5.06


Regards,  

MrB

 P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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