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topjm [15]
3 years ago
10

Let's say we have a triangle with sides called a, b, and c, and that b is the base. Our triangle has a height that we'll call h.

If a = 11 inches, and b = 3 inches, and c = 11 inches, and h = 10.89 inches, what is the area of this triangle in square inches? Round your answer to the nearest hundredths place. 16.3 16.34 21.9 21.89
Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

16.34 square inches.

Step-by-step explanation:

Given:

Base of triangle, b = 3 inches

Height of triangle, h = 10.89 inches

Question asked:

What is the area of this triangle in square inches?

Round your answer to the nearest hundredths place .

Solution:

As we know,

Area\ of\ triangle =\frac{1}{2} \times base\times height

                           =\frac{1}{2} \times3\times10.89\\\\ =\frac{32.67}{2} \\\\ =16.335

As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.

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A discrete graph is a series of scatter plot points. It means point on graph aren't continuous manner.

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3 0
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What is the probability of choosing a pair that contains ONLY cards labeled with the letters B, C, or F?
Nezavi [6.7K]

Answer:

Pr = \frac{1}{6}

Step-by-step explanation:

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r = 2 --- selection

Required

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So, we have:

n = First * Second

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Pair = \{(B,C), (B,F), (C,B),(C,F),(F,B),(F,C)\}

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4 0
3 years ago
A wooden artifact from an ancient tomb contains 20 percent of the carbon-14 that is present in living trees. How long ago, to th
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Answer:

The artifact was made approximately 13,306 years ago

Step-by-step explanation:

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The formula for radioactive decay is given by the equation:

N=N_0 e^{- \lambda t}\\where:\\N = Number\ of\ particles\ at\ time\ t\\N_0= Number\ of\ particles\ at\ time\ t_0\\\lambda = decay\ constant = \frac{In}{t_{1/2}} ; t_{1/2} = half-life\\t = time\ in\ years

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t ≈ 13,306 years

7 0
3 years ago
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