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uysha [10]
3 years ago
10

An acute isosceles triangle has an angle of 80° that is located across from the longest side in the

Mathematics
1 answer:
Natali [406]3 years ago
8 0

An

Step-by-step explanation:

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Solve the equation below
Agata [3.3K]
Set up the equation:

4(8.75x-2)=97
35x-8 =97
35x =97+8
35x =105
x. =3

The value of x is 3.
7 0
2 years ago
The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance wo
Keith_Richards [23]
This question has this set of answer choices:

a) when the plane cuts three faces of the cube, separating one corner from the others

b) when the plane passes through a pair of vertices that do not share a common face

c) when the plane is perpendicular to the base and intersects two adjacent vertical faces

d) when the plane makes an acute angle to the base and intersects three vertical faces

e) not enough information to answer the question

The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others

You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.

8 0
2 years ago
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Use the correct order of operations to calculate5 1/2 * 4 1/2 -7/2/ 2 1/3​
IgorC [24]
If there are multiple operations at the same level on the order of operations off from left to right and you work like this first noticed that there are no parentheses or exponents so we moved to multiplication and division with any sense of parentheses
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=p%5E%7B3%7D%20at%20%5C%5C%5C%5C%20p%20%3D%202" id="TexFormula1" title="p^{3} at \\\\ p = 2" al
WITCHER [35]
<h3>Answer:  8</h3>

Reason:

Replace p with 2 and evaluate.

p^3 = 2^3 = 2*2*2 = 8

Think of a cube that is 2 units along each side. It's volume is 2*2*2 = 8 cubic units. Repeated multiplication can be shortened to using exponents.

Another example: 7^4 = 7*7*7*7

6 0
1 year ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
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