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avanturin [10]
3 years ago
12

Solve the following equations for r: 9r - 66 = 116 - 4r

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

r = 14

Step-by-step explanation:

9r - 66 = 116 - 4r

+4r                 +4r

13r - 66 = 116

     +66    +66

13r = 182

divide both sides by 13

r = 14

Hope this helps!!!

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Cube A has a volume of 125 cubic inches. The edge lengths of cube B measure 4.8 inches. Which cube is larger and why?
Anestetic [448]

Answer: Cube A is larger. This is because volume is found by multiplying length × width × height. The length, width, and height of a cube are ALWAYS equal. Therefore if cube B has a length of 4.8 inches it also has a height of 4.8 inches and a width of 4.8 inches. To find its volume multiply 4.8×4.8×4.8 this will give you 110.592 cubic inches. This means cube A is larger.


4 0
4 years ago
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Liula [17]

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6 0
3 years ago
Help me please. 30 points :)
Nataly [62]

\frac{(5 \:  -  \: 8x)}{( \sqrt{5 \:  -  \: 8x} )}  \:  =  \:  \sqrt{5 \:  -  \: 8x}
For the result to be Real,
5 \:  -  \: 8x \:  \geqslant  \: 0
8x \:  \leqslant  \: 5
x \:  \leqslant  \:  \frac{5}{8}
( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \:  \times  \:  (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \:  =  \:  \frac{ {(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
Hence,
\frac{{(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
is the required form.

3 0
4 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
I need help ASAP nowwwwwww plz 106=
polet [3.4K]

Answer:

r = 0.053 or 5.3%

Step-by-step explanation:

Formula:

I = Prt

Given:

I = 106

P = 10000

t = 73/365

Work:

I = Prt

r = I/(Pt)

r = 106/(10000 * 73/365)

r = 106/2000

r = 0.053

6 0
3 years ago
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