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blagie [28]
3 years ago
14

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square w

ith a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.
A- 196 cu in.
B- 47 cu in.
C- 1038 cu in.
D- 226 cu in.
Mathematics
1 answer:
mina [271]3 years ago
3 0
The volume of the frustrum is the difference in the volumes of these two pyramids: 
<span>30 * 5^2 / 3 - 18 * 3^2 / 3 </span>
<span>= 750/3 - 162/3 </span>
<span>= 250 - 54 </span>
<span>= 196 cubic inches.
</span>
You're Answer is <span>A- 196 cu in.</span>
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\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 186&100\\ 47.90&x \end{array}\implies \cfrac{186}{47.90}=\cfrac{100}{x}\implies 186x=4790 \\\\\\ x=\cfrac{4790}{186}\implies x\approx \stackrel{\%}{25.75}

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