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Tatiana [17]
3 years ago
8

LCM and GCF of 150:600 and 900????pleas help I didn't get the ratio part​

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

LCM: 1,800

GCF: 150

Step-by-step explanation:

150:600 = 150 / 600 = 0.25 (that's pretty much what a ratio is, just a fraction or part of a whole.)

150 is the greatest common number that will factor into all three, and the least/smallest number they all multiply into is 1,800

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A Family purchased tickets to the movies in spent a total of $40.75. The family purchase five tickets there was a $.90 processi
muminat

Answer:

$7.25

Step-by-step explanation:

Total amount spent on the ticket   = $40.75

Number of ticket purchased  = 5

Processing fee per ticket  = $0.90

Unknown:

Cost of each ticket = ?

Solution:

To solve this problem, we need to find the processing fee for the 5 tickets purchase;

      Processing fee = number ticket x processing fee per ticket

      Processing fee  = 5 x 0.9  = $4.5

Now, the real cost a ticket = $40.75  - $4.5  = $36.25

So, cost per ticket is;

        Cost  = \frac{36.25}{5}   = $7.25

7 0
3 years ago
Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd<br><br>​
Lilit [14]

9514 1404 393

Answer:

  -(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

  \displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}

5 0
3 years ago
Find an equation that is perpendicular to the x-axis and passes through the point (7,13)
rjkz [21]

Answer:

x = 7

Step-by-step explanation:

A line perpendicular to the x- axis is a vertical line parallel to the y- axis.

The equation of a vertical line is

x = c

where c is the value of the x- coordinates the line goes through

The line goes through (7, 13) with x- coordinate of 7, thus

x = 7 ← equation of perpendicular line

4 0
3 years ago
Melody want to sell bags of mixed candy at her lemonade stand . She will mix chocolates pieces that cost $4.89 per bag with pean
Alja [10]

Answer:

Bags of chocolates pieces = 10 bags

Bags of peanut butter pieces = 15 bags

Step-by-step explanation:

The ratio of chocolate pieces to peanut butter pieces

($4.23-$ 3.79) : ($ 4.89 - $4.23)

= $0.44 : $0.66

=  2 : 3

Therefore; the fraction of chocolate pieces bag = 2/5

Thus; Number of bags of chocolate pieces = 2./5 × 25

                                                                        = 10 bags

Fraction of peanut pieces bags = 3/5

Therefore; Number of bags of peanut butter pieces = 3/5 × 25

                                                                                      = 15 bags

7 0
4 years ago
Read 2 more answers
Please help
harkovskaia [24]

Answer:

Sergio's strategy was to multiply the sum of the length and width of the rectangle by 2. This was one correct way to find the perimeter of the rectangle.

Jamie's strategy was to add the given measurements of the length and width of the rectangle together. This was another correct way to find the perimeter of the rectangle.

Karina's strategy was to multiply the given length of the rectangle by 2 and add this product to the width of the rectangle. This was NOT a correct way to find the perimeter of the rectangle, as it did not follow the formulas to finding the perimeter of a rectangle: l + w + l + w, or 2(l + w) and furthermore formulas that explain the same thing. Karina only multiplied the length by 2 and did not account for the width of the retangle which she should have done as well.  

Ethan's strategy was to multiply the width by 2, multiply the length by 2, and add these two products together to find the perimenter. This final strategy was correct, and can be used to find the perimeter of the rectangle.

Hope this helps you! I love doing math, so enjoy!

3 0
2 years ago
Read 2 more answers
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