20.
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The integral that is needed to solve the demand function is R(x) = 599x - 0.14
A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.
Here, given differential equation;
R'(x) = 599 - 0.21
we can also write this as;
On integrating both sides, we get
R(x) = + C
R(x) = 599x - 0.14 + C ...........(i)
Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get
0 = 0 - 0 + C
C = 0
Put the value of C in equation (i), we get
R(x) = 599x - 0.14
Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14
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Answer: He sold 10 pounds of cashews .
Step-by-step explanation:
Since we have given that
Selling price of walnuts = $4.00 a pound
Selling price of cashews = $7.00 a pound
Number of pounds of walnuts = 10
Let number of pounds of cashew be x
Total price at which he sold a mixture = $5.50
According to question,
Hence, he sold 10 pounds of cashews .