The answer is b= - 5/2
- 6 (b + 3)= - 8 + 5
- 6b - 18= - 3
- 6b= - 3 + 18
- 6b= 15
b= - 15/6
b= - 5/2
Answer:
16
Step-by-step explanation:
-8--------------------------0---------------------------8
imagine this is a straight line where you can measure the distances.
to get from -8 to 0 we have a distance of 8 units.
so, knowing this, now from 0 to 8 we have another distance of 8 units.
8+8=16
Distance is the absolute value, meaning that it'll always be positive.
Answer:
a) ![A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C1%26-1%261%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}0\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
b) 
c) ![A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%266%5Csqrt%7B2%7D%20%260%5C%5C%5Csqrt%7B3%7D%20%263%5Csqrt%7B3%7D%20%260%5C%5C2%26-16%260%5Cend%7Barray%7D%5Cright%5D)
![x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=x%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Csqrt%7B2%7D%20%5C%5C%5Csqrt%7B3%7D%20%5C%5C6%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
a) considering the equation:
Minimize 
(matrix A)
vector b
![b=\left[\begin{array}{ccc}0\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
b) If Pxn is matrix B and p-vector d, we have:
minimize 
![Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]](https://tex.z-dn.net/?f=Ax%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-6%260%5C%5C-4%263%260%5C%5C1%268%260%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C1%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
![Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1](https://tex.z-dn.net/?f=Ax-b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-bx_%7B2%7D%2B4%20%5C%5C-4x_%7B1%7D%2B3x_%7B2%7D-1%20%20%5C%5Cx_%7B1%7D%2B8x_%7B2%7D-3%20%20%5Cend%7Barray%7D%5Cright%5D%20%3D1)

c) minimize 
in matrix:
![A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%266%5Csqrt%7B2%7D%20%260%5C%5C%5Csqrt%7B3%7D%20%263%5Csqrt%7B3%7D%20%260%5C%5C2%26-16%260%5Cend%7Barray%7D%5Cright%5D)
![x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=x%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Csqrt%7B2%7D%20%5C%5C%5Csqrt%7B3%7D%20%5C%5C6%5Cend%7Barray%7D%5Cright%5D)
16 games they won in total 28 ÷7 is 4 and they won 4 games in each 7 games so 4 times 4 is 16
Answer:
<u>The correct answer is A. 22 inches ³</u>
Step-by-step explanation:
Let's recall that the formula of the volume of a triangular pyramid:
Volume = 1/3 * Area of the base * height
Replacing with the values we have:
Volume = 1/3 * 11 inches² * 6 inches
Volume = 66/3
Volume = 22 inches ³
<u>The correct answer is A. 22 inches ³</u>