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guapka [62]
3 years ago
13

What is it. Please do you carry the negative or the square first.

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

(3)

Step-by-step explanation:

5x^2 - (2x-3)^2

5x^2- (2x-3)(2x-3)

now you distribute, the 5x^2 stay the same for now

So for now just (2x-3)(2x-3)

first 2x * 2x= 4x^2

2x * -3= -6x

-3 * 2x= -6x

-3 * -3= 9

So (2x-3)(2x-3) is 4x^2 -6x-6x+9

You can simplify that to 4x^2 -12x +9

Now we add in the 5x^2 from the start don't forget!

And we are subtracting sooo

5x^2 -(4x^2 -12x +9)

5x^2 -4x^2 +12x -9

x^2 +12x -9

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The subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

Given that

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According to the question

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

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                   \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)

  • Step2; Rewrite terms that are subtracted as the addition of the opposite.

        \rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)

  • Step3; Group-like terms.

                   \rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\

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                    \rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3

                   

Hence, the subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

To know more about Polynomial click the link given below.

brainly.com/question/26078031

                   

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