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Len [333]
3 years ago
14

Can a scatter plot show a linear association but neither a positive nor a negative association?

Mathematics
2 answers:
vodomira [7]3 years ago
8 0
Yes, it's called no association. 

I hope this helped! Please take the time to rate, pick the Brainliest answer (not necessarily mine!), and thank me if you feel I helped with this question! Thank you, it helps me a lot. :) 
wolverine [178]3 years ago
8 0
Yes of course it can.<span />
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Arsenic is toxic to humans. The greatest amount of arsenic that is allowed in drinking water is 10 parts per billion. A test sho
Anna35 [415]
The decimal you put would be “two ten-millionths” if read out loud. If the allowable amount is 10 parts per billion, it would be 1 part per 100 million. Because 2 parts per 10 million is also 20 parts per 100 million, it is not not an acceptable amount
3 0
3 years ago
Answer quickly please
olga nikolaevna [1]

Answer:

linear I think so ................

3 0
2 years ago
Read 2 more answers
What is the value of p?
Misha Larkins [42]

Answer:

D. 43°

Step-by-step explanation:

interior angle to 90°=90°

interior angle to 133°=47°

p=180°-47°-90°=43°

please mark as brainliest

7 0
3 years ago
what is the probability of seeing a sample mean for 21 observations less or equal to the sample mean that we observed
kramer

Answer:

P(x \le 21) = 0.69146

Step-by-step explanation:

The missing parameters are:

n = 64 --- population

\mu = 20 --- population mean

\sigma = 16 -- population standard deviation

Required

P(x \le 21)

First, calculate the sample standard deviation

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{16}{\sqrt {64}}

\sigma_x = \frac{16}{8}

\sigma_x = 2

Next, calculate the sample mean \bar_x

\bar x = \mu

So:

\bar x = 20

So, we have:

\sigma_x = 2

\bar x = 20

x = 21

Calculate the z score

x = \frac{x - \mu}{\sigma}

x = \frac{21 - 20}{2}

x = \frac{1}{2}

x = 0.50

So, we have:

P(x \le 21) = P(z \le 0.50)

From the z table

P(z \le 0.50) = 0.69146

So:

P(x \le 21) = 0.69146

4 0
2 years ago
5% of adults participate in at least 30 minutes of exercise each day. How likely is it that a randomly chosen adult will exercis
MaRussiya [10]

Answer:

5 out of 100 adults so not very likely

6 0
3 years ago
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