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2 years ago

14

Can a scatter plot show a linear association but neither a positive nor a negative association?

2 answers:

vodomira [7]2 years ago

8 0

Yes, it's called no association.

I hope this helped! Please take the time to rate, pick the Brainliest answer (not necessarily mine!), and thank me if you feel I helped with this question! Thank you, it helps me a lot. :)

wolverine [178]2 years ago

8 0

Yes of course it can.<span />

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ANTONII [103]

Answer:

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2 years ago

40 miles x 25 min.=?mph

Natalka [10]

$\bf \stackrel{miles}{40}~in~\stackrel{minutes}{25}\implies \cfrac{40~miles}{25~\underline{minutes}}\cdot \cfrac{60~\underline{minutes}}{hr}\implies \cfrac{40\cdot 60~miles}{25~hr}
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\cfrac{2400}{25}\cfrac{miles}{hr}\implies 96\frac{miles}{hr}$

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2 years ago

3 cans of soda and 2 chips is 5.35, 2 cans of soda and 4 chips is 6.90. whats the cost of each item ?

boyakko [2]

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1 year ago

A commuter must pass through 5 traffic lights on her way to work and will have to stop at each one that is red. She estimates th

sergij07 [2.7K]

Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

Let <em>X</em> = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

$\mu=E(X)=\sum x.P(X=x)$

The formula to compute the standard deviation of <em>X </em>is:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}$

The formula of E (X²) is:

$E(X^{2})=\sum x^{2}.P(X=x)$

(a)

Compute the expected value of <em>X</em> as follows:

$E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2$

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

$E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58$

Compute the standard deviation of <em>X</em> as follows:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3$

Thus, the standard deviation of <em>X</em> is 1.3.

4 0

3 years ago

Read 2 more answers

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rusak2 [61]

Answer:

x=3,y=7

Step-by-step explanation:

8x+3y=45

2x+3y=27

8x-2x=6x

45-27=18

<u>6</u><u>x</u><u>=</u><u>1</u><u>8</u>

6. 6

x=3

2x+3y=27

2(3)+3y=27

6+3y=27

3y=27-6

<u>3</u><u>y</u> = <u>2</u><u>1</u>

3. 3

y=7

3 0

2 years ago