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lutik1710 [3]
3 years ago
11

rom a group of 5 managers (Joon, Kendra, Lee, Marnie and Noomi), 2 people are randomly selected to attend a conference in Las Ve

gas. What is the probability that Marnie and Noomi are both selected?
Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

probability that Marnie and Noomi are both selected=0.1

Step-by-step explanation:

A group of 5 managers (Joon, Kendra, Lee, Marnie and Noomi), 2 people are randomly selected to attend a conference in Las Vegas.

the possibility of selecting 2 from 5 manages is 5C2 ways

5C2= \frac{5!}{2!(5-2)!} =10

There is only one choice of selecting Marine and Noomi from 5 managers

So probability of selecting Marine and Noomi is

\frac{1}{10} =0.1

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Answer:

P(2450

And we can find this probability with this difference:

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If we use the normal standard table or excel we got:

P(-1.96

And that represent 95% of the data. so then the percentage below 2450 is 2.5% and above 4390 is 2.5 %

Step-by-step explanation:

Let X the random variable that represent the birth weights of a population, and for this case we know the distribution for X is given by:

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And we can use the z score formula given byÑ

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If we apply this formula to our probability we got this:

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If we use the normal standard table or excel we got:

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And that represent 95% of the data. so then the percentage below 2450 is 2.5% and above 4390 is 2.5 %

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