What is the work to 2×6÷3+3^2

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0

4 years ago

An insurance company has 10,000 automobile policyholders. The expected yearly claim per policyholder is $240, with a standard de

elena55 [62]

Answer:

almost 0%

Step-by-step explanation:

Given that for an insurance company with 10000 automobile policy holders, the expected yearly claim per policyholder is $240 with a standard deaviation of 800

using normal approximation, the probability that the total yearly claim exceeds $2.7 million is calculated as follows:

Sea sumatoria de x = SUMX, tenemos que:

$P (SUMX \geq 2700000) = P(\frac{SUMX - 240*10000}{800 *\sqrt{10000} } \geq \frac{2700000 - 240*10000}{800 *\sqrt{10000} })$

$= P (z\geq \frac{2700000 - 240*10000}{800 *\sqrt{10000}})$

= P (z => 3.75)

= 1 - P ( z < 3.75)

P = 1 - 0.999912

P = 0.000088

Which means that the probability is almost 0%

4 0

3 years ago

Find the quotient of 902÷27 (It has a remainder)

Amanda [17]

Answer:

The quotient of 902 divided by 27 equals 33 and the remainder is 11.

7 0

3 years ago

The recipe for sugar cookies requires 5 cups of flour to 3 cups of sugar. If Alex uses 15 cups of flour, how many cups of sugar

svp [43]

9 Cups. I 5*3=15 so 3*3=9

8 0

3 years ago

Read 2 more answers

John wants to find the perimeter of a square with side length 2p - 5. Write two expressions that represent the perimeter, includ

kenny6666 [7]

Answer:

More people died in Auschwitz than the British and American losses of World War Two combined. About 60 million Reichmarks - equivalent to £125m today - was generated for the Nazi state by slave labour at Auschwitz. Nazis at Auschwitz offered some non-Jewish female prisoners the option of 'light work

Step-by-step explanation:

3 0

3 years ago