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3 years ago

Whats the answer for this one plz

Mathematics

2 answers:

BartSMP [9]3 years ago

7 0

It’s 90* :)!!!!!!!!!!!!

Pavlova-9 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

X = 90°

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(-5qsquaredp) to the 8th power

Viefleur [7K]

Answer:

Step-by-step explanation:

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4 years ago

A town has a population of 7000 and grows at 4% every year. What will be the population after 13 years, to the nearest whole num

Andre45 [30]

Answer:

Step-by-step explanation:

7,000 × 1.04¹³ = 11,656

5 0

3 years ago

Prove, Cosec2A + cot2A = cotA

elena-s [515]

Proved

Step-by-step explanation:

Cosec2A + cot2A = cotA

On Left hand-side

$Cosec2A + cot2A = \frac{1}{sin2A} +\frac{cos2A}{sin2A} \\\\\\$

$=\frac{1}{2sinAcosA} +\frac{2cos^2A-1}{2sinAcosA}$

$\frac{1+2cos^2A-1}{2sinAcosA} \\\\\\=\frac{2cos^22A}{2sinAcosA} \\\\=\frac{cosA}{sinA} \\\\\\=cotA$

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Trigonometric ratios: brainly.com/question/12462203

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8 0

3 years ago

Write the equation of a line that is perpendicular to y=2/7x +9 and that passes through the point (4,-6).

Allisa [31]

Answer:

$y=-\frac{7}{2}x+8$

Step-by-step explanation:

Given the equation

$y\:=\:\frac{2}{7}x+9$

comparing the equation with the slope-intercept form

$y =mx+b$

Here,

m is the slope

y is the intercept

so the slope of the line is 2/7

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

the slope of the perpendicular line will be: -7/2

Therefore, the point-slope form of the equation of the perpendicular line that goes through (4,-6) is:

$y-y_1=m\left(x-x_1\right)$

$y-\left(-6\right)=\frac{-7}{2}\left(x-4\right)$

$y+6=\frac{-7}{2}\left(x-4\right)$

$y+6-6=\frac{-7}{2}\left(x-4\right)-6$

$y=-\frac{7}{2}x+8$

3 0

3 years ago

What is the solution to the inequality? -2/3(2x - 1/2) ≤ 1/5x - 1 Express your answer in interval notation.

almond37 [142]

ANSWER

$-\frac{2}{3}(2x-\frac{1}{2})\le \frac{1}{5}x-1$

Multiply through by LCM of 15

$(15) \times -\frac{2}{3}(2x-\frac{1}{2})\le 15(\frac{1}{5}x-1)$

$-10(2x-\frac{1}{2})\le 3x-15$

Expand brackets to obtain,

$-20x+5\le 3x-15$

Group like terms

$15+5\le 20x+3x$

$20\le 23x$

$\frac{20}{23}\le x$

$x\ge \frac{20}{23}$

In interval form it is written as

$[\frac{20}{23}, \infty)$

8 0

3 years ago