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klasskru [66]
4 years ago
7

The equation of a line is y = mx + 2. What is the value of m (the slope) if the line passes through point A(−5, −18)?

Mathematics
1 answer:
Kitty [74]4 years ago
6 0
We can input the point
remember that (x,y)
so we are given (-5,-18)
so when x=-5, y=-18
so

-18=-5m+2
minus 2 both sides
-20=-5m
divide both sides by -5
4=m
m=4
answer is 2nd option
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X/3 = 5/x-1 cross multiply
defon
15/2x-1
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8 0
3 years ago
Pls help me with this multiple choice !
lana66690 [7]

Answer:

D

Step-by-step explanation:

\sin(60)  =  \frac{6 \sqrt{3} }{x}  \\ x =  \frac{6 \sqrt{3} }{ \sin(60) }  = 12 \\  \tan(60)  =  \frac{6 \sqrt{3} }{y}   \\ y =  \frac{6 \sqrt{3} }{ \tan(60) }  =   6

8 0
3 years ago
12 = 3 x *blank* × *blank*
mario62 [17]
1.(first blank) 2
2.(second blank) also 2
So 2 and 2
EXPLANATION:
3 x 2 is 6.
6 x 2 is 12.
Boom Im magical
3 0
3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
3 years ago
7/8 5/6 which one is bigger
Novay_Z [31]

your answer is 5/6 is bigger
4 0
4 years ago
Read 2 more answers
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