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Rzqust [24]
3 years ago
10

The question is in the picture.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0
A is the correct answer. I have already done this and got A and it was right. I hope it is the same to yours. :D


I hope this helped!
kherson [118]3 years ago
6 0
The correct answer is A, I have also had this question before and it is A. Hope this helps! :) 
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My answer is wrong but i don’t know how
Nitella [24]

Answer:

Answer is B

Step-by-step explanation:

-1/5 is the answer.

If you need work just let me know

7 0
3 years ago
Please help me !!!!
liq [111]

Answer:

...

against the wind, an airplane travels 3640 km in 7 hours.

with the wind, the same plane travels 6000 km in 6hrs.

...

let speed of plane in still air be x mph

speed of wind be y mph.

..

t=d/r

..

against wind speed = x-y mph

with wond speed = x=y mph

...

3640/(x-y)=7

3640 = 7x-7y

/7

520=x-y.....................1

...

6000/x+y = 6

6000 = 6x+6y

/6

1000=x+y.....................2

...

Add (1) & (2)

2x=1520

/2

x=760 mph speed of plane in still air

...

plug value of x in 2

1000=760+y

100-760=y

240 = y

240 mph speed of wind

8 0
3 years ago
Please help.......!!!!!!!!!!
Studentka2010 [4]

Answer:

20 feef

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
A restaurant made 12 pizzas in 15 minutes. How many pizzas would the restaurant make per hour?
Novay_Z [31]
The restaurant will make 48 per hour
4 0
3 years ago
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In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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