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STALIN [3.7K]
3 years ago
12

I dont have a question anymmore lol k thanks

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0
Have a great day ;) I hope this was helpful.
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What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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3 years ago
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I need 5-10 please i really need help getting my grade up
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Matthew worked a summer job and saved $900 each
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1400

Step-by-step explanation:

hope that helps <3

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What is the decimal equivalent of 714.45\9<br><br>​
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Step-by-step explanation:

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Statistics Practice Q8
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The answer is B, at first the sum is 621 and then you divide by 7 to get your median (88), after you add the two #s of 86 and 87 to 621 and divide by 9. Resulting in the median being 88
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